## Answers

Son: The data given for carnot refrigeration cycle are mzo Tmin - The cop of & COP = car onot TL = TH-Ti nax = 1.25. Work input.

W= 25 KI Refrigeration cycle is Tmin e t- Tmax - Tmm - Tmax T max- Temin cop Tmin e Tras-1 top-1.25 -1 = 0.25, :. (cop=25= 4) also, cop= RE TRE = 4x 25 = 160 KT) R.E Cop= E = 4x 25 = 100 kJ W .R - The T-S and Pr-y diggram for Carnot refrigeration cycle co PV=C 0 OVOU PV=c pvc - > - V~ from p-v diagram it is observed that and also obsered that, T2 = 73=Tmax emin is at state I Ti Tha Tmin) - (for R-12, 8=1.14) (7) _ 6.154 0 = ( Thaime lei14- 12 = ( Tmax ) - 1 = ( 1025 ) 119-1 Tihan] V2 = 4.923 -

- compressor work for cannot refrigeration cycle as, d a n W.R- P2 : V2-PIVI - MR C T2-T - o. gog, 0.0688. (T2-TDX103 1.14 - -(for R-12, R = 0.0608 Kol ng k) Dit is 100 25X103 = 0.909 X6-0688x18 (T2-TD 1:14-1 - 2 - = 15.9 x - 2) . - Tmar- Tmin= 55.965- (3) But Tomar Tmn ):25 PRC ont bils Sao TDA Tminx1.25- Tmin= 55.965 0.25 Tmin= 55.965 Tmin= 223.9kZ: Tmax = 279.825k/

i.

Properties of R-12 at Tmin=223.9k v=0.3831 m3/kg, but mrt 2, N=0.3482 m)

,, PV = m РТ. Р. = oqoyxo. 06 88 х 10 х 223 Ф• 3482 JP, – Pm) = 4o. 21ч ЕР° |

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