1 answer

How to determine the Cartesian equation using parametric equations?

Question:

#x=Sec t y=Tan t, t belongs s to (pi/2, 3pi/2) #


Answers

#x^2-y^2=1#
#x<0#

Explanation:

Given:
#x=sect#
#y=tant#
for all
#t>pi/2#
and
#t<3pi/2#
we know that
#sec^2t-tan^2t=1#
#x^2-y^2=1#
#x<0#

.

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