1 answer

How do you solve #4.19=-log x#?

Question:

How do you solve #4.19=-log x#?

Answers

Convert log to exponent form and solve. The solution is given below.

Explanation:

#4.19 = -log(x)#
#-4.19=log(x)#
#log(x) = -4.19#

Use the rule #color(brown) (log(x) =k => x=10^k#

#x=10^(-4.19)#

.

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