1 answer

How do you solve #3x+y=4# and #2x+y=1#?

Question:

How do you solve #3x+y=4# and #2x+y=1#?

Answers

#(3, -5)#

Explanation:

I used substitution.

Isolate #y# in one of the equations.
#3x+y=4#
#y=4-3x#

Substitute #y# in #2x+y=1# for #4-3x#.
#2x+(4-3x)=1#
#2x+4-3x=1#
#4-x=1#
#-x=-3#
#x=3#

Substitute #x# back into #y=4-3x# find the value of #y#.
#y=4-3(3)#
#y=4-9#
#y=-5#

Answer (Coordinate Form): #(3, -5)#

.

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