1 answer

How do you simplify #64^(-4/3)#?

Question:

How do you simplify #64^(-4/3)#?

Answers

#1/256#

Explanation:

Using the #color(blue)"law of exponents"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(a^(m/n)=(root(n)(a))^m" and "a^-mhArr1/a^m)color(white)(2/2)|)))#

#rArr64^(-4/3)#

#=1/(64^(4/3))#

#=1/(root(3)(64))^4#

#=1/(4)^4#

#=1/256#

.

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