1 answer

How do you integrate #int (x^(3/2)+2x+1)dx#?

Question:

How do you integrate #int (x^(3/2)+2x+1)dx#?

Answers

#2/5x^(5/2)+x^2+x+c#

Explanation:

Integrate each term using the #color(blue)"power rule for integration"#

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(int(ax^n)dx=a/(n+1)x^(n+1))color(white)(2/2)|)))#

#rArrint(x^(3/2)+2x+1)dx#

#=1/(5/2)x^(5/2)+2/2x^2+x+c#

#=2/5x^(5/2)+x^2+x+c#

where c is the constant of integration.

.

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