1 answer

How do you get #12*mol# of ammonia from #6*mol# dinitrogen, and #12*mol# dihydrogen?

Question:

How do you get #12*mol# of ammonia from #6*mol# dinitrogen, and #12*mol# dihydrogen?

Answers

Well, first correct the stoichiometry....

Explanation:

#1/2N_2(g) + 3/2H_2(g) rarr NH_3(g)# OR

#N_2(g) + 3H_2(g) rarr 2NH_3(g)#

We work from the stoichiometric coefficients of the LATTER, which INSISTS that ONE EQUIV of dinitrogen REACTS with THREE EQUIV of dihydrogen to give TWO EQUIVS of ammonia.

To get 12 mole of ammonia, CLEARLY we require 6 mole of dinitrogen....and 18 mole of dihydrogen. Do you agree? The bozo who set this question doesn't....

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