1 answer

How do you find the roots, real and imaginary, of #y= -4x^2 + x^2 +6# using the quadratic formula?

Question:

How do you find the roots, real and imaginary, of #y= -4x^2 + x^2 +6# using the quadratic formula?

Answers

#color(indigo)("Roots are " x = -sqrt(3/2) , sqrt(3/2)#

Explanation:

#y = -4x^2 + x^2 + 6#

#y = -3x^2 + 6#

#a = -3, b = 0, c = 6#

#x = (0 +- sqrt(0 +96)) / -8#

#x = sqrt96/-8, sqrt96/8#

#color(indigo)("Roots are " x = -sqrt(3/2) , sqrt(3/2)#

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