1 answer

How do you find the area enclosed by the x-axis and the given curve #y=(6/x)# for x between -4 &

Question:

How do you find the area enclosed by the x-axis and the given curve #y=(6/x)# for x between -4 & -2?

Answers

Area # = int_-4^-2(6/x)dx = 6 ln (1/2) #

Explanation:

Simply integrate the function y=(6/x) between the bounds given, -4 and -2.

# int_-4^-2(6/x)dx = 6 int_-4^-2 1/x \ dx #

# " " =6 [ln |x|]_-4^-2 #

# " " = 6 { ln |-2| - ln |-4 } #
# " " = 6 { ln 2 - ln 4 } #
# " " = 6 { ln (2/4) } #
# " " = 6 ln (1/2) #

.

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