1 answer

How do you factor #16a^2-121#?

Question:

How do you factor #16a^2-121#?

Answers

#(4a+11)(4a-11)#

Explanation:

This can be factored using difference of squares. Both terms are perfect squares.

#a^2-b^2=(a+b)(a-b)#

First, let's find the square root of each term.

#sqrt(16a^2)=4a#

#sqrt121=11#

#(4a+11)(4a-11)#

.

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