1 answer

How do you evaluate the limit #sin(6x)/cos(4x)# as x approaches #0#?

Question:

How do you evaluate the limit #sin(6x)/cos(4x)# as x approaches #0#?

Answers

# lim_(x rarr 0) sin(6x)/cos(4x) = 0 #

Explanation:

We seek:

# L = lim_(x rarr 0) sin(6x)/cos(4x) #

We note that both #sintheta# and #cos theta# are both continuous well behaved function and that both are defined when #theta =0#

Thus:

# L = (lim_(x rarr 0) sin(6x))/(lim_(x rarr 0) cos(4x)) = sin0/cos0 = 0/1 = 0 #

.

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