## Answers

F'(x) = x(e^x) + e^x

= e^x(x+1)

= 0 for a max/min of f(x)

so e^x = 0 ----> no solution OR

x+1 = 0

x = -1

f(-1) = -e^-1 = -1/e

I will let you decide if it a max or a min.

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