1 answer

Horizontal Distance

Question:

A person whose eyes are H = 1.54 m above the floor stands L =2.25 m in front of a vertical planemirror whose bottom edge is 43 cm above thefloor, Fig. 23-48. Whatis the horizontal distance x to the base of the wallsupporting the mirror of the nearest point on the floor that can beseenreflected in the mirror?

Answers

From the figuretanθ =(H - h) / L= (1.54m - 0.43m) / (2.25m)θ= 26.26oThen in the another traingletanθ = (0.43m) / xtan26.26o = (0.43m) / xx = (0.43) / (tan26.26o)= 0.87m.

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