horizontal links are hinged to a wheel. how can youdetermine thevalue of P and the reaction at A?
Answers
All the procedure is correct. however, there are some mistakes.
1. fx is -120 N
2.θ = tan^-1( Ay/ Ax)= (90/ -120)= - 36.86˜ - 36.9. thetangent in the third quadrant is negative and the angleθ is measured from the - x axis to thedirrection ofA.
.
Consider the free body diagram of the wheel
consider summation of moments about 'A'ΣMa = 0=> -P*a+90*100 = 0=> P = 120 NBy applying equilibrium conditionsΣFx = 0=> Ax = P = 120 NΣFy = 0=>Ay = 90 NA = √(1202+902)= 150 Nθ = tan-1(90/150) = 30.960.
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