## Answers

Pi (1+0:2 Mail] 3. Ti = 340k P, = 550kpa VI 3 124m/s 20 Athout = 8.4cm Menit 2016 I p befose shock = P x = 148.5 kpa Inlet Macken 2. = MART m/s = 364.61 - / 4х287xзцо Ma, vi ai 124 369.61 20.33 stagnation temp :- (24) 2 2x(1005) = 347.643 Tit a z 340 + To = Tit 20p Stognation pren we = 550 $50 (170.23(0.373) Po.

2593.08kpa at Hout M=1 PA -0.528 Po let - 313.14624 kpa To 20.834 * = 290k

mut -CALXV thout = T8R Ishoul 11.4x287X290 ✓ thood - 341.357) Psh xh = Monorrtth 2. Johan = eshsout RT those Cthroat = 3.36 kg/m3 in shrout Ishrat Alhout thout = 3.36 *8.4x16x341.35 Divine in ghosecut 1.07 kg/ mnozzle ? P =COT 550 = Cx0.28 7*340 G=5 = 5.63 164 ? full Mosole zl, Aqva A in AX (1+0.2xMef 13 1.728 Mai i+0:2X60-332 AL (1+04 8.ux104 1.728 x0.23

from normal sock table A, -0.001571 m2 A m, = GIAN 0 42 25.68X0.001571 X 124 m = 1.09 Kgl Pa = 148.5*pa Esentropic flow B 148.5kpa 593.08kpa -0.25038 Po. M = 142 (before the shock trave) Tz То 20.5756 T2= = 200.10K 20.35 M2 = 102 M2=0.25 (k-1) Maz²+2 (0.4x 1.92² +2) 24 Maz?- (k-1) 2x14x1.92²-04 (mock numbers after sock uzove) [2k ma? (k-1) [2+(K-1) maup] (k+1)2 mai 2 [2x1481972–ay (2km? (] = {2+(x-) MB] (214) ²x 1.923 TE Tz (2+04x1.92). 1162

TE T2 -1.62 T3 = 162X Tz -1.62x200.10 [T =324.876 (Temp after shock) Sony point 3-4 (asentropic How) (Paz =Poy) a 1 Tos = toy at Mg = 70.35 [1 +0.2 M32] 3:57 Pane = (1+0.28 037) RA Pz P2 Ktol (2xm;< gr-1] man (2x14x1922-04) = 4.1342 2 2.4 Pet 24.134XB = 4.134X148.5 = 614 kpa Pos = {1+0.2X03847** *61Y = 668.28 Toza [1+02x0.382] XT3 - [1 +0-260362)* 324.87 Toz = 382.821 - Toy AA16 at Me =0.16 3.5 3.5 Pay = (1 +0.2(Me}] - {1+22X(016)] Py = =/656.uukpa = Pe ' Poy=P03 668-28 1.018

To Ти [1+0.263)?] {1+02 (Over] Tu = 33282 liol - 331 IC ko Te -881K Pe=lexRTO 656.44 = lex0.287X331 € 56.4 kg) is 2364.68ms zve Veruit zorte 1.4x287X331 = Ce feve 1.09 = @ 6.9 x AeX364.68 2 Ae = 4.33x104 A = 4,3 cm

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