1 answer

Homework: Chap 3,Section 3 Score: 0 of 1 pt x3.3.17 7 of 10 (10 complete) HW...

Question:

Homework: Chap 3,Section 3 Score: 0 of 1 pt x3.3.17 7 of 10 (10 complete) HW Score: 90%, 9 of 10 pts Question Help A standard dock of cards contains 52 cads. One cand is selactod from the dack (a) Compute he probablilty cf randomly selecing a twe or bwo b) Compute the probablity of randomly selecing a five or two or sie (c) Compulta the probsbiity of randomly selecing a tive or treart. a. Pltve or two)-015 (Round to theee decimal places as needed.) b. Ptfhwe or two or six)Round to three dscomis places as neoded) your answer in the anawer box and then cäck Check Answer

Homework: Chap 3,Section 3 Score: 0 of 1 pt x3.3.17 7 of 10 (10 complete) HW Score: 90%, 9 of 10 pts Question Help A standard dock of cards contains 52 cads. One cand is selactod from the dack (a) Compute he probablilty cf randomly selecing a twe or bwo b) Compute the probablity of randomly selecing a five or two or sie (c) Compulta the probsbiity of randomly selecing a tive or treart. a. Pltve or two)-015 (Round to theee decimal places as needed.) b. Ptfhwe or two or six)Round to three dscomis places as neoded) your answer in the anawer box and then cäck Check Answer

Answers

A deck of 52 Cards

a.

No. of five's in the deck => 4

P(five's) = 4/52

No. of two's in the deck => 4

P(two's) = 4/52

Probability = > P(five's) + P(two's) = 8/52 = 2/13 = 0.154

b.

No. of Five's = No. of two's = No.

Of six = 4

Total => 4+4+4 = > 12

Probability ( Selecting five or two or six ) = 12 / 52

= 0.231

c.

A five or a heart

No. of fives => 4

No. of hearts => 13

No. Heart five's => 1

Total cards( five or a heart ) => 13 + 4 -1

= 16

Probability => 16/ 52

= 0.308

.

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