1 answer

Help!!!

Question:

In Figure 22-30, particle 1 of charge q1 =-5.00q and particle 2 ofcharge q2 = +3.00q are fixed to anxaxis.As a multiple of distance L, at whatcoordinate on the axis is the net electric field of the particleszero?

Answers



We know that for the negative charge electric field is radiallyinwards.
For the positive charge electric field is radially outwards.
So at the point P the direction s E1 and E2 are in the oppositedirections.
Let us consider point P is at a distance of d from the charge-5.00q.
Now the magnitude of the electric field at the point P due to thecharge -5.00q is

Magnitude of the electric field due to the charge +3.00q at thepoint P is

Now at the point P net electric field is zero and E1 and E2 are inthe opposite directions.
So





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