2 answers

Heat

Question:

How much heat is evolved when 320 g of SO2 is burned according to the chemical equation shown below?
2 SO2(g) + O2(g) ? 2 SO3(g) 2Ho
rxn = -198 kJ

Answers

2SO2 + O2= 2SO3 ?H= -198KJ/MOLE
Here 2 moles of SO2 on combustion produces 198 KJ of energy
1 mole of SO2 = 64 g
2 moles of SO2 = 128
so, 128 g produces 198 KJ
320gr of SO2 produces ,

(198/128)*320 KJ
that is = 495 KJ

THE AMOUNT OF HEAT PRODUCED IN THE ABOVE REACTION IS 495 KJ.

2SO2 + O2= 2SO3 ΔH= -198KJ/MOLE

Here 2 moles of SO2 (M.Wt=2x32+32=96gr) on combustion produces 198 KJ of energy

320gr of SO2 produces is

320grx198/96gr= 6.6x102 KJ/mole

THE AMOUNT OF HEAT PRODUCED IN THE ABOVE REACTION IS 6.6X102 KJ/MOLE

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