1 answer

You have hot water of a mass Minitially at 80°C. You add ice, initially at 0°C,...

Question:

You have hot water of a mass Minitially at 80°C. You add ice, initially at 0°C, to bring the mixture to 20°C. Which of the fo

You have hot water of a mass Minitially at 80°C. You add ice, initially at 0°C, to bring the mixture to 20°C. Which of the following is a correct expression for the mass of ice you must add? (Ignore the container) O MO Cwater X 60°C Cice x20°C OM Cuter X 60°C Cuater 20°C+Lice O MG Cwater X60°C Cice x20°C+Lice O MC Cwater X 60°C Lice

Answers

Solution:

At equilibrium,

Heat added = heat removed

m_{ice}\left ( C_{ice}\times \left (20^{o}C-0^{o} C \right )+L_{ice} \right )=MC_{water}\times \left ( 80^{o}C-20^{o}C \right )

m_{ice}=M\frac{\left (C_{water}\times \left ( 80^{o}C-20^{o}C \right ) \right )}{\left ( C_{ice}\times \left (20^{o}C-0^{o} C \right )+L_{ice} \right )}

m_{ice}=M\left (\frac{C_{water}\times 60^{o}C }{ C_{ice}\times 20^{o}C+L_{ice} } \right )

Answer : option 3

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