## Answers

**Question 1:**

Given: mu (4-41) X, + 321 X2 +0 -0 ; (4+41) *, -3272 =0 x (4+42) = (4-hi) (4+42) X, at 321 (4+42) x2 =0 - (16+16) x + 32 (41-4) X2=0 = 2, + (-4+47) x2 = 0 3

(4-42) = (4+4) 4-42) x - 32(4-42) x₂ = 0 (16 + 16 )x, – 32(4-42) X₂=0 → 32x + (-4+4i) x₂ =0 6 Equations and 6 are the same ① and ② are the same. Infinite Solutions exist. - From : (4+4i) x = 32x2 → (X, 1 x2) = (+, (+1).+) x + L - ansito answer

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