## Answers

Sol Transformation equation of Sheam Stress's For Finding shear stress on any oblique plane which is at angle (o) for the given Verticle plane. Tyr exy V e (I) T Ge ay Cay o (TL) Cry Pages Cyx (I) We know that shear stress is second order tonsor . Then we convort into force Force = stress x Asra 0 For Pure Shear Ox Ex=oy=0 Exy = lyx Coso= Po Base PR hy potenuse Sino OR hypotenust ( peopendincular PR

Exy [Pa xe o aso) (3x 8d) hx2 Jo > XC lyx Corxe]] Oxyl (PR xe) ( CBR x C) Sino [t= thickness of free surface] By equating 6 Cose Oxy CP Q x €) Cos O = Tyx (OR х4) sinot Cry (PR x4) Exy Pa Coso = Cyx (OR) Sino + Ox'y' (PR) ExY (PR) - Gay (PR Sino. Sino + Qxy (PR Coga). > Oxly' = {xy [ Cozze - Sin?e] We know [Cos? o - Sinzo] = COS2O > Cely' = Day C0520 Her ca option (D) is right answon.

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