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Five cubic feet of an aqueous hydrochloric acid (HCl) having a molarity of 2.0 is to...

Question:

Five cubic feet of an aqueous hydrochloric acid (H
Five cubic feet of an aqueous hydrochloric acid (HCl) having a molarity of 2.0 is to be prepared. Assuming the SG of the solutions is 1.02, determine: (a) How many gram of pure HCl is needed? (b) How many liters of pure water is needed? (c) What is the mole fraction of HCl in the solution? (d) What is the mass fraction of HCl in the solution?

Answers

1 cubis feet = 28.3 Lit or 28.3 kg of water

5 cubic feet = 5 X 28.3 = 141.5 lit of water having 2M of HCl

HCl moleculer weight + 36.46

Molarity = W/M.WtX 1/Lit

2 = W/ 36.46 X 1/141.5

a). Weight of HCl = 2 X 36.46 X141.5 = 10318.18gr

b). 141.5 lit of water need

c). mole fraction of HCl

HCL moles = 10318.18/36.46 = 282.99 mole

H2O moles = 141500/18 = 7861.11 moles

mole fraction of HCl = 282.99/ 282.99+7861.11= 0.035

.

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