1 answer

Find the measure of the larger angle of two complementary angles such that one half the larger is 15 more

Question:

find the measure of the larger angle of two complementary angles such that one half the larger is 15 more than one-fourth the smaller angle.

Answers

Let x be the smaller angle &y be the larger angle. y/2=15+x/4 x+y=90 y=90-x (90-x)/2=15+x/4 (90-x)/2-x/4=15 [4(90-x)-2x]/2*4=15 (360-4x-2x)/8=15 360-6x=8*15 360-6x=120 -6x=120-360 -6x=-240 x=-240/-6 x=40 degrees is the smaller angle 40+y=90 y=90-40 y=50 degrees is the latger angle. Proof: 50/2=15+40/4 25=15+10 25=25.

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