1 answer

Find an equation of the line satisfying the given conditions Through (-4,3); perpendicular to -8x+5y=77 possible answers: 5x+8y=4 5x-8y=77 -8x-5y=4

Question:

Find an equation of the line satisfying the given conditions
Through (-4,3); perpendicular to -8x+5y=77
possible answers:
5x+8y=4
5x-8y=77
-8x-5y=4
5x-8y=4

Answers

Find an equation of the line satisfying the given conditions Through (-4,3); perpendicular to -8x+5y=77 ------------------ Find the slope of -8x+5y=77 by putting it in slope-intercept form y=mx+b (that means solve for y). -8x+5y=77 5y = 8x + 77 y = (8/5)x + 77/5 The slope, m, is 8/5. Lines perpendicular will have a slope that's the negative invervse, m = -5/8. ------------------ y-y1 = m*(x-x1) where (x1,y1) is the point (-4,3) y-3 = (-5/8)*(x+4) 8y-24 = -5x - 20 5x+8y = 4.

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