## Answers

You can probably use a one-sample t-test for this data. You'll need to calculate the mean and standard deviation. Here's a t-test formula:

t = (sample mean - population mean)/(standard deviation divided by the square root of the sample size)

Hypotheses:

Ho: µ = 24 -->null hypothesis

Ha: µ does not equal 24 -->alternate hypothesis

Once you do the calculations, use a t-table to determine the cutoff to reject the null at .05 level of significance for a two-tailed test using 7 degrees of freedom (df = n - 1 = 8 - 1 = 7).

Does the test statistic exceed the cutoff (critical) value from the table? If it does not, you cannot reject the null and conclude a difference. If it does, then reject the null and conclude a difference.

I hope this will help..

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