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pH is determined using Henderson-Hasselbalch equation as-
pH =pKa + log [Conjugate Base]/[Acid]
We were unable to transcribe this image
We were unable to transcribe this image
Now, [A] + [B] = 0.045 mol [A] = 0.00513 mol So, [B ] = 0.03987 mal I Now, we have 0.03987 mol of Naoh. X L x 1.36 mol L. Naon = 0.03987 mol of Noon 1 x = – 0.02932 Na oh 0,03987 1.36 .: 293 mL of naon must be added.
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Pe 1
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