1 answer

Determine the centroid of the bracket shown knowing the radius of the hole, r, is 0.5...

Question:

Determine the centroid of the bracket shown knowing the radius of the hole, r, is 0.5 in, and the height, h, is 2.2 in Glve t
cos(x) + 2 h 2 in 2 in The centroid is located at X in and Y in.
Determine the centroid of the bracket shown knowing the radius of the hole, r, is 0.5 in, and the height, h, is 2.2 in Glve the answer to the nearest .001 inch, An integral table ( x values are all in radians) COS +2) dx = sin( + 2x 9.81859 in? -2 cos) + 2) dar sin + cosa O in -2 +2) da 2 sin + 2 x cosa 10.9747 in' 2 + 2 dir sin 24 + 2 sin 12.44799 in 13 sin(2)+11 22 COS 21. 6234 in ? sin 3 - - 2
cos(x) + 2 h 2 in 2 in The centroid is located at X in and Y in.

Answers

•Cos(x) +2. r=0.5 in. 2.2 in ke 2 in 2 in od T. YdA E AY sy JdA EA А, 9, Ý = Ay, A2₂ A,+A₂ A3 (oux2.2) ( 22 ) A4, = = 9.68 inAzY2 - 1 / ( Cosca) + 2) Cos(x) +2) da from table, entegration 2 [ (cos(x) +2) Jaux = 12.44799 in? - 2 3 .. A₂Y2 12.44799 incX - Aix, + A₂ - AX3 A+ A₂-Az Ax = (2.2x4) (0) y y -0.</p><p>A282= sta t x da Area da = y da. xtda 2 2. 2 Ax2 = x. (y dx). - 2 2 AX2A, x, + A1 - A₂ X 3 X = A + A₂-A3 oto-O Ait A₂-A3 Since the cross section is Symmetrical about y-axis, x=0) Centroid is locatI hope you will understand the answer and please thumbs up...

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