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Ans: 0 = 3.9, 62 = 2.7 ny = 18 M2 = 16 34.22-31.88 2.0518 31ge 2.72 18 my P value = -222 van Giren, Ho: 41-42=0 against th: 11-1270 Boy Calculating, weget ti = 34122 j5 = 31.88 $ =005 Test statistic Zoo 4 - Xe 522 + site 0.0402 As pralue < 0.0529, So Reject tto. 6) for the for tee 95% Cortidence intenval Lodz 1996. - The 95%. Catidence interral is (34.22 - 31:88) - 1.96 <Hi 82 3(34.22-31188) +1696/8 0.105 3/4-A2 < 4.575 with 95% Confidence the troue difference in the means in between 0.105 and 4.575. Because zero is not Contained in this interral, we concludes there is a significant difference between the means we reject the mall hypothesis.
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Ay 3192 + 2.7² 18 16 i 0 2 are love, p= 4/2012 - 4 = 4(16 off- + [ 0.21] -4 -31) -1.96 3192 2.7² 18 76 - 0.00010 0.58317 0.58307 power = 1-6 = -0.58307 417
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