Answers
Solution :
Given :
Power of lens (P) = 0.75 D
Since : f = 1/P = 1 / (0.75 D) = 1.33 m
And, we have :
Near point for Normal vision = 25 cm
Distance of glasses from the eyes = 2.2 cm
Thus : Object distance (u) = 25 cm - 2.2 cm = 22.8 cm = 0.228 m
Let, the near point for the eye be : x
Therefore: Image distance (v) = x - 0.022 m
Now Using lens equation :
1/f = 1/u + 1/v
1/1.33 = 1/ 0.228 - 1/ (x - 0.022)
1/1.33 = 1/ 0.228 - 1/ (x - 0.022)
-3.636 = - 1/ (x - 0.022)
x - 0.022 = 0.275
x = 0.297 m = 29.7 cm
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