## Answers

83 C b 12m 3m 200 KN 3m d Ra Rd 1 vo syn +T EMC=0 200x3 Rdx6 Rd = 100 KN → Ans Efx=0 Areal How diagram - 100 KN Ans SOKN b +TEMA=0 100 KN - 200x3 +Vx12 Va = 50 kN/ & Ans OKN] (-) (+) Efyzo it Va= 50KN a Ans a 50KN a 50 KN

shear Jolie Liagram Ans 50KN 50KNA 100KN (+) 100 KN b (+) IODIN (-) d 100KN bending moment diagram Arus 6CC KN-M с b 600 KN-m (-) 3 300 KN- a

Qy d e 8m um 2m 'b 120 KN 4m R; Ra T Art VA so "PEMA MA =0 12oxy Vfx 12 Arual flow diagram 1 vf 40 KN 7. And 26.66 kN 26.66 kN (-) 40 KN d Efy zo 17 40KN VA = 40 kN & Ans b. qEmo Emd zo (RUS) (+1 Rfx6 40x4 Rf - 26.66 KN Ans 40 KN f 40KN Efx=0 I Ra= 93.33 KN ſ Ans

Qy d e 8m um 2m 'b 120 KN 4m KRE Ra T Vf VA so "PEMA MA =0 12oxy Vfx 12 Arual flow diagram 1 vf 40 KN 7.

And 26.66 kN 26.66 kN (-) 40 KN d Efy zo 17 40KN VA = 40 kN & Ans b. qEmo Emd zo (RUS) (+1 Rfx6 40x4 Rf - 26.66 KN Ans 40 KN f 40KN Efx=0 I Ra= 93.33 KN ſ Ans

shear flow diagram 40KN 4 OKN 26.66 KN 26.66 KN d e C 9 31 33 KN b (+) 26.66 KN a .9 3.33 KN f Bending Moment diagnam 320kN-m 320 kN-m 160KN-M (+) e a (-) 373,33 KN-M 160KNM -) (4) Q f

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