Answers
20l of air bubbles /hr into 1 liter broth
Air contain 20% pure oxygen
20liter air X 20/100 = 4 liter oxygen pure oxygen provided
25% is resolved of O2 disolve
Means 4L O2 x25/100=1lit
1liter 02 disolve /liter of culture / hour
1 liter = 1000ml
1000ml of oxygen resolve /liter of culture / hour
ml/L is equivalent to part pr thousand
But the volume of gases is not equivalents to mass it can be calculated by gas law
PV=nRT
where
P
= pressure in atm (1 atm = 1000mb = 101.3 kPa)
V
= volume in liters
n
= moles of gas
R
= gas constant (for these units, =0.0821 L*atm/mol*K
T
= temperature in Kelvins ( T(K) = T(degC) + 273K )
1atmX1lit of oxygen=nX0.0821x293k
n= 1atmx1liter of oxygen/0.0821X293k
356.881molO2/liter
MW of oxygen 32.0g/mole
1 mol contain 32 g oxygen
356.881 mol contain 32x356.881
=11420.19 or 11421 g
1g =1000mg
11421x1000=
Disolve oxygen =11421x10 -3mg O2/liter of culture / hour
Provided oxygen 11421x10-3 x 4=45684 x 10-3mg 02/liter of culture / hour
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