## Answers

Vf = Vo(t) - 32(t)

Vf = 88 - 32t or t = 2.75sec.

Height reached from 25 ft. height

h = 88(t) - 32(t^2)/2

h = 88(2.75) - 16(2.75)^2 = 121 ft.

It takes the same 2.75 sec. to return to the original launch height of 25 feet and an increment more to fall the 25 feet further to the ground.

Therefore,

h = Vo(t) + 32(t^2)/2

(121 + 25) = 0(t) + 16(t^2)

t - sqrt(146/16) = 3.02

The time from launch to impact is therefore (2.75 + 3.02) = 5.77 sec..

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