Answers
Mean = = 41
Standard deviation = = 8.2
a)
We have given P(X < x) = 0.90
z value 0.90 is 1.28
We have to find the value of x
b)
We have to find P(39 < X < 42)
For finding this probability we have to find a z score.
That is we have to find P( - 0.24 < Z < 0.12)
P( - 0.24 < Z < 0.12) = P(Z < 0.12) - P(Z < - 0.24) = 0.5485 - 0.4037 = 0.1449
( From z table)
c)
We have to find P(X > 45)
For finding this probability we have to find z score.
That is we have to find P(Z > 0.49)
P(Z > 0.49) = 1 - P(Z < 0.49) = 1 - 0.6872 = 0.3128
( From z table)
d)
If the probability that pecan tree to have a height greater than 45 feet is less than 0.05 we say that it is unusual.
But P(X > 45) = 0.3128 > 0.05 so it is not unusual.
e)
Sample size = n = 36
We have to find P( > 45)
For finding this probability we have to find z score.
That is we have to find P(Z > 2.93)
P(Z > 2.93) = 1 - P(Z < 2.93) = 1 - 0.9983 = 0.0017
( From z table)
f)
If the probability that mean height pecan tree 45 feet is less than 0.05 we say that it is unusual.
In this case P( > 45) = 0.0.0017 < 0.05 so it is unusual.