(b) Propane must be stripped from an oil stream in a stripping column by using pure...

Fabar project Steam + pro pane 0 Propane foil X = 26% X, - male patio g parpane in och = mole of poopane @ more of odp - AL OORS = 0.02564. 1-X 1-0.025 T=300k | p = 1.2atal pure steam X2 = mole of poopane mole of oil = X, + (1-0.9) 90% is stripped) = 0.02564* 0.1 = 0.002564 given, - 1872.46 Hg) = 15.726 - 18 T(K)- 25.16 from geven condition, 1872.46 Inps. - 15.726 -- 350-25-16 mp = 9,9617 bus - ps = 2199.7958 mmity. = 27.894 atm.

Nated as Y= mx At equilibrium, u= mx can be approximat Y = f xx (from Raoult's law). → Y= 27.894X= 23. 245x ie Y= 23245 *} 1.2

minimumtion tt pmpane balance - Les molor flowsate of pure oil = 150kmah Gs - molar flowsate of pare steam to X, + GeY = Leta + GsY, . - Le (X, - *2) - Ge (Y, -Y) - Garmin - La (x,- X2) at minm condition (gas) M.- Y X, and Y, are out e equilibrin 150 10.02564 - 01002564) Y = mx Gsmin - - (23.2458 0.02564 -0) = 3.4614 - 5.8077 kmol /ho. ( 23, 245x0.02564) (Gemin= 5.8077 kmst /ho G = 1.7 Gemin = 9.8730 9 kmother 150 - 15.

1928 Gs 9.87309

Y at Ge=1.76 smin Ls (X, -42) = Ge (Y,-Y₂) >> y = 150(0.0054 -0.00254) to 9.87309 = A-Ls/he - m 0:35058 15-1928 23. 245 = 0.65359 By Kremses equation, NTP = ln xo - Yn ym . 1 Ynty + (1-A) TA] - in 1x - 72/m +(1-4) +A) 1 X2 - Yt/m [10.02564 - 03/23.045 0.002564 - 07/23245 - 065359) +0.65359 in (0.65359) → NTP = 3.331 ~ 4.. By Macabe Theile method, equilibrium linee Y=mx equilibrin line 0.005 0.01 0.015 0.02 0.116225 0.23245 0.348675 0.4649 0.581125 0.27 011 0.025 0128005 0:01 0.015 002 0.025 0.03 0.035 x from graph, no of stages a 4.