## Answers

As per given information in Q19:

If 'A' as spacer and nucleotide T, C and G are in triplets then number of codons would be available are :

Number of codons= (number of nucleotide) ^{3}

For T, C and G (since no. of nucleotide are 3 )= 3^{3} = 27.

For A, T, C and G ( since no. of nucleotide are 4)= 4^{3} = 64.

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