## Answers

**A)**

**Null Hypothesis:** Population mean radiation level (for the three locations) could be **equal**

**Alternative Hypothesis:** At least one of the population mean radiation level (for the three locations) could be **unequal**

**B)**

**Number of Treatment (t) = 3 n = 24**

T_{1} (Sum of Location A) = 636, T_{2}(Sum of Location B) = 702, T_{3}(Sum of Location C) = 643

G = grand total = 1981

CF = Correction Factor = G^{2}/N = 1981^{2} / 24 = 163515

Where, r = 8

SSTR = (1/8) * (636^{2} + 702^{2} + 643^{2}) - 163515

SSTR = 328.6

SSE = TSS - SSTR

SSE = 656 - 328.6

SSE = 327.4

MSSTR = SSTR/t-1 = 328.6 / 3-1 = 164.3

MSSE = SSE / n-t = 327.4 /24-3 = 15.6

**F = MSSTR / MSSE = 164.3 / 15.6 = 10.54**

**P-value: 0.0007** ............................From F table

P-value < , i.e. 0.0007 < 0.05, That is Reject Ho at 5% level of significance.

Therefore, At least one of the population mean radiation level (for the three locations) could be **unequal**

ANOVA | |||||

Source of Variation | SS | df | MS | F | P-value |

Between Groups | 328.6 | t-1=3-1 =2 | 164.3 | 10.54 | 0.0007 |

Within Groups | 327.4 | n-t=24-3 =21 | 15.6 | ||

Total | 655.9583 | n-1=24-1 =23 |

**Test statistic: F = 10.54**

**P-value: 0.0007** ............................From F table

**ANSWER: A. Yes**

**Yes, Reject the Null Hypothesis.**

**ANSWER: B. No**

**No, population means Not equal**