1 answer

Air is trapped in a piston cylinder arrangement. The air expands from a temperature of 60...

Question:

Air is trapped in a piston cylinder arrangement. The air expands from a temperature of 60 C and a pressure of 280 KPa to a pressure of 140 KPa. During the process, 30 KJ/Kg of work is done and 14 KJ/Kg of heat is removed. The initial volume is 0.00878 m^3.

a) What is the mass of the air?

b) What is the temperature change during this process?

c) What is the entropy change during this process?

d) Does the air gain or lose entropy during this process?


Answers

Povi - MRT 280 x 0.00876 27% 0.287 x(41226) (ol Hass of the air T 0.0257 *9 (9) mrop zo de 30 dua + 14 44 lgby mcv(T-05) -44.hn- z killag mc, di 1x 0.71&x &T= -44 (1) dT 61,28°C Temperatae change (e) Extrapy change ds am[eplen (3) -R In CD [lioossede

.

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