Air enters a diffuser at 102 KPa , 57 Celcius , and 285 m/s and exits...

given diffuser with inlet & outlet states. Idiffuser P = 102kPa P = 303kPa T = 57c T: 10°C V=285 m/s V, 12 m) A-97 cm Find air rate ( lcgls) of i) flow an behaves air ideal gas الدم) assuming PV= MRT have where R = gas wastant for and 3k RT P m air intet, Now at

V.

0.287 >> (kpa.my)-(571273) * kg.k 102 Kla 3 Vi 0.9 285 mi kg. inlet. air at the This is opeific volume of Now a = volumetic flowrate in Q where * m3 m 2 velocity Area a= 2 * 285 m Q 97 cm ²* Coleman) 2.7645 m3 (2)

mi 2.7645 mi m3/s 0.9 285 ms kg m 2.9 7 7 kg/s exit the area of the diffuser :- b) Find 15 wnserved, Now man min mont is outtet, specifi volume Now 0.287 kPa.m 3 V₂ c10+273) < RT2 Pr lcg.k mz 303 kPa m 22 h 0.2 680 m3/kg ma (3)

mi, my 12 cm) A₂ (m²) * * 2.977 ( kg ) = 0 2630 m3 kg m2 2.977 * 0.2680 0.06648 12 6 64.8 633 cm² 100 cm 0.066 48 m rate :- heat transfer c) Average + the control volume the Taking diffuser egn og energy conservation the applying dE. à - Wer & Emil hint V ] - Emont [hout & Vont at

heat transfer N. work done by diffuser = 0 opeipi enthalpy V.

Velocity decu have nteady flow he nine dt [ hint on the a: Emont [hout & Vouth] - Emin wrditions, P = 303 kPa, Tr = 10 c outlet at 13 hout 282.96 ( from air thermodynamic table) kg T,= 57°C, P = 102 kPa at inlet wonditions hina 330.852 kg (5)

mini mout now ::. in [ (hout -hin) + 놀 (Vont Vin?)] L Ą. 2.999 kg I (262.90 - 350.359) 4 (1242 285") ma 2.977 1-47.892 ko i 405 40.5 با leg m :1000 1000 1 TUVO Nm kg Heim) kg now KJ : kg kg 'm² IL 1 m2 RI ט טטן - 1000 SI kg 40.54 os mi? -47.892 lug 2.Q: 2.977 19 [ kg 1 kw |- 263.263 kw KI * Q - - 2 63.263 KI/ heat out of control volume. ove nign indicates (1