1 answer

A uniform electric field measured over a square surface with side length d = 13.5 cm...

Question:

A uniform electric field measured over a square surface with side length d = 13.5 cm makes an angle θ = 67.50 with a line normal to that surface, as shown in the figure below. If the net flux through the square is 5.30 N·m2/C, what is the magnitude E of the electric field (in N/C)? N/C

A uniform electric field measured over a square surface with side length d = 13.5 cm makes an angle θ = 67.50 with a line normal to that surface, as shown in the figure below. If the net flux through the square is 5.30 N·m2/C, what is the magnitude E of the electric field (in N/C)? N/C

Answers

Area , A = 0.135^2 m^2

theta = 67.5 degree

let the electric field is E

electric flux = E * A * cos(theta)

5.80 = E * 0.135^2 * cos(67.5 degree)

solving for E

E = 831.6 N/C

the electric field is 831.6 N/C

.

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