Answers
Of water. kilograms. at (initially) , donk contains 70 kg ho tas. 918) 40 kg COI b Let's the tank librated evention de quation. contains (70 kg of salt hence the initial condition is A (0) = 70 kg The di differential equation in A'tho da = reate in rate out The rate will be * rate i.e, Concentration of the form amount of salt (kg ofy water (L) rate (l/min) amount GE on N B612
0.4kg /L* 16 L/ min rate of Rate in = * 6.4 kg /min Rate the tank going out: The solution drains from the toplo, ale tohle to get The amount of solution is also ahalying with respect to time. solution is coming in at 164/min and a at 4 L/min hence after every min we Liquid solution is leaving have tank. extra 1210 of The amount cat time t i then of liquid 2000 tlat Thus the rate out is Akg (20007 lat) L 1x (4 L/min) GA 2000 tlat kg/min B612
1000+ 6t If e 2. ! ln 1000 + 6t IA 6 e 7 ln 1000 +67 1 If = e Answer If= (1000 +67) 73 by log properties (2) The colution of equation i) is If A- If. Q at (1000 + 6t) A= | (100+ 6.4 1.6.4 dt us (1000+ 6+) A 6.4 (1000+ 6+) 13 413 (loopt 6+) A= 1000+ 6t) tc at t=0 A (0) = 70 kg B612
Importy into The put to . Alt) = 4.8t + Box --309 (1ooot67) kg concentration of salt in the solukon. in the tank approacher as time approaches infinity . B612 infinite