1 answer

A steel plate contains 0.82% C and the surface is going to be carburized. The carburization...

Question:

A steel plate contains 0.82% C and the surface is going to be carburized. The carburization takes place such that the surface composition is 3.0% C, how long will it take to have 2.4% C at a depth of 0.55 mm into the plate at a temperature of 560 °C?erf(2) 7 erf(x) Z erf(2) 0 0 0.55 0.5633 1.3 0.9340 0.025 0.0282 0.60 0.6039 1.4 0.9523 0.05 0.0564 0.65 0.6420 1.5 0.9661 0.

erf(2) 7 erf(x) Z erf(2) 0 0 0.55 0.5633 1.3 0.9340 0.025 0.0282 0.60 0.6039 1.4 0.9523 0.05 0.0564 0.65 0.6420 1.5 0.9661 0.10 0.1125 0.70 0.6778 1.6 0.9763 0.15 0.1680 0.75 0.7112 1.7 0.9838 0.20 0.2227 0.80 0.7421 1.8 0.9891 0.25 0.2763 0.85 0.7707 1.9 0.9928 0.30 0.3286 0.90 0.7970 2.0 0.9953 0.35 0.3794 0.95 0.8209 2.2 0.9981 0.40 0.4284 1.0 0.8427 2.4 0.9993 0.45 0.4755 1.1 0.8802 2.6 0.9998 0.50 0.5205 1.2 0.9103 2.8 0.9999

Answers

carbon on steel plate Warto concentractions of be calculated by the following expressio time can CA Cho =l- erf C) CAO CAS cr

0872477 1- erf :co erf ) = 0.27523 ⓇE 0 0 208965 Z a 1] Oizu8465 21 DE Z TE 2 [0x0.248965 2 Z A- o) do X0-248965 2 0:55x10 3

Here diffusion rate is not given ,so we need to use above formula.if you have D value please comment below.i will check my answer

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