1 answer

A solution is prepared by dissolving 0.69 mol of MgCl2 in 0.50 kg of water. A.)How...

Question:

A solution is prepared by dissolving 0.69 mol of MgCl2 in 0.50 kg of water.

A.)How many moles of ions are present in solution? (Express your answer to two significant figures and include the appropriate units)

B.)What is the change in the boiling point of the aqueous solution? (Express your answer using two significant figures)


Answers

a A 0.69 males of My cla - Mg Cl in 0.5kg water Mg 2+ Coy) & a ce Coo) Now so I Mach boom 3 lona Males of ion present = 3 xo.please don't forget to press thumbs up thanks for posting questions

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