## Answers

proteins 9.ug. carbohydrater - ug.

.
Pats - 3.0g. Energy from components proteins = (9.ogx 4.0 calon) & 36.0 cal Carbohydrates - 3 g x 4.0 calgn) = 172 cab Eat = (3.0g x 9.0 calg & 27. 0 cob Total colorie = (2700 + 172 + 36.0) cal . = 235 cal Now I cal = 2. 235 cal = = 4.184 T.

(235 x 4. 184 T 483.24 J is its used to temperature This amount of energy heat water and raise q = cp. m. DT . m= long - 1000 g cp = 4.18 J groen T 1 - 25.0°C I let T be find Temperature a.

983.24 J = (4.18 Jg noc (1000 g) (T-25.0°C (T- 25.0°C) = (u. 18 Jgnac 2000 g) I- 25.0°c - 0.235°C [T = 25.2350 de final Temperature

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