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A mass 2.4 kg of solid laurasium is initially at temperature 6∘C. It is put into...

Question:

A mass 2.4 kg of solid laurasium is initially at temperature 6∘C. It is put into contact with 3.8 kg of liquid tethium which is at temperature 97∘C, and the two chemicals are thermally insulated from the rest of the universe. The specific heat capacity of solid laurasium is 1165Jkg∘C, and the specific heat capacity of liquid laurasium is 3495Jkg∘C. The melting point of laurasium is 22∘C, and the latent heat for its solid liquid transition is 25149Jkg. The specific heat capacity of liquid tethium is 2330Jkg∘C. This material does not undergo a phase transition in this problem. What is the final equilibrium temperature of the laurasium and the tethium? Answer in degrees Celsius. Ans. 54.4


Answers

Solution we have put 214 kg of solid laurasium into a 3.8 kg of liquid te thium at gi°c. heat lost by liquid te thium heat ga

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