Let the speed of train be #T# and that of car be #C#.

As he covers #250# km by train and rest by car i.e. #370-250=120# km. As it takes him #4# hours, we have

#250/T+120/C=4# **...................(A)**

and if he travels #130# km by train and the rest i.e.

#370-130=240# km by car, it takes #4# hrs. and #18# min. i.e. #43/10# hours and

#130/T+240/C=43/10# **...................(B)**

Now multiplying **(A)** by #2# and subtracting **(B)** from it, we get

#(500-130)/T=8-43/10=37/10#

(note that second term on LHS cancels out)

or #370/T=37/10#

i.e. #T=(370xx10)/37=100#

Putting this in **(A)**, we get #250/100+120/C=4#

or #5/2+120/C=4# or #120/C=4-5/2=3/2#

or #3C=120xx2=240# i.e.

#C=80#

i.e. speed of train is #100# km. per hour and speed of car is #80# km. per hour.