## Answers

In fuel cell the reactio takes place as follows

anode reaction CH_{4} + H_{2}O -------> CO_{2} + 8H^{+} + 8 e^{-}

Cathode reaction 4O_{2} + 8H^{+} + 8 e^{-} ---------> 4H_{2}O

Overall reaction CH_{4} + 2O_{2} -----------> CO_{2} + 2H_{2}O

So, from here it is clear that 1 mole of CH_{4} produces 8 moles of Hydrogen

So, molar mass of H = 1 g/ mol

no. of moles of H present = given mass/ molar mass = 4000 g/1 g = 4000 moles

So, no. of moles of CH_{4} present = 500 moles

molar mass of CH_{4} = 16 g/mol

So 500 moles = 500 moles * 16 g/moles = 8000 g = 8 kg

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