## Answers

The ball's horizontal velocity component is a constant 104/2.80 = 37.14 m/s. The initial vertical velocity component must be 37.14 tan28.5 = 20.17 m/s

Next, compute the height Y of the ball 2.80 s after it is hit

Y = 1.04 + 20.17*2.80 - (g/2)*(2.80)^2

Subtract 3.0 m from that for the fence clearance distance..

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