Answers
Given:
[Ba(OH)2] = 2.75*10^-3 M
So,
[OH-] = 2*[Ba(OH)2]
= 2*2.75*10^-3 M
= 5.50*10^-3 M
a)
use:
pOH = -log [OH-]
= -log (5.5*10^-3)
= 2.26
Answer: 2.26
b)
use:
PH = 14 - pOH
= 14 - 2.26
= 11.74
Answer: 11.74
c)
Since pOH > pH, this is basic
Answer: Basic
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