## Answers

I am not really obliged to work out molar quantities for this problem. I started with 10.0 g; I finished with a 8.00 g mass of mercury metal and a 1.35 g mass of HgO. The outstanding mass, 0.65 g, *must* have been lost as oxygen gas.

#### Explanation:

Mass is conserved. I started with a 10.0 g mass; I drove off a 0.65 g mass of oxygen gas.

All the mass of the chemical reaction must sum to the starting mass.

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