Answers
Vo home mdes of Hask = 11 $123 Imole mole Volume conc. f N2 Imol/ moles of 12 = 2 modes conc. of 12 of 12 = mole o 2 = 2 mol/L Volume И, (4) Kc = 50.5 = 101 2 + 12 (9) = 213782 initial conce I mol 2 mol/L equ cone.
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(1-x) meyl (2-x) mu! (23) L. Ke= {4172 2 (201² [12] [17] (1-» (2-2) 42² 101 2 x²-3x+ 2 10176- 303 87 202 = 842 93x?- 303a+202-0 -6303) 1 (303)-4893x202 2893 303 I 16665 303 129 186 186 So, possible value of x=0.94 So, equilibrium concentration on [n]) = 24 = 270.99 = 1.38 [H2] - -7221-0.94=0.06, (1) = 2= 2-0.94 - 1-06 x =- 2
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